Base | Representation |
---|---|
bin | 100110101110110001001… |
… | …0100110110100011010011 |
3 | 200211212212222022202200021 |
4 | 1031131202110312203103 |
5 | 1144203214203110420 |
6 | 15153223241204311 |
7 | 1056403505256652 |
oct | 115354224664323 |
9 | 20755788282607 |
10 | 5323114113235 |
11 | 177257a164186 |
12 | 71b7a4190697 |
13 | 2c7c767c7649 |
14 | 1458d65dd199 |
15 | 936ee2317aa |
hex | 4d7625368d3 |
5323114113235 has 4 divisors (see below), whose sum is σ = 6387736935888. Its totient is φ = 4258491290584.
The previous prime is 5323114113223. The next prime is 5323114113299.
5323114113235 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5323114113235 - 233 = 5314524178643 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 5323114113235.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 532311411319 + ... + 532311411328.
It is an arithmetic number, because the mean of its divisors is an integer number (1596934233972).
Almost surely, 25323114113235 is an apocalyptic number.
5323114113235 is a deficient number, since it is larger than the sum of its proper divisors (1064622822653).
5323114113235 is a wasteful number, since it uses less digits than its factorization.
5323114113235 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1064622822652.
The product of its digits is 32400, while the sum is 34.
The spelling of 5323114113235 in words is "five trillion, three hundred twenty-three billion, one hundred fourteen million, one hundred thirteen thousand, two hundred thirty-five".
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