Base | Representation |
---|---|
bin | 100110101110111010101… |
… | …0110111010100100110111 |
3 | 200211220201020011021201220 |
4 | 1031131311112322210313 |
5 | 1144204342423433421 |
6 | 15153315045121423 |
7 | 1056414433323501 |
oct | 115356526724467 |
9 | 20756636137656 |
10 | 5323433421111 |
11 | 1772723425993 |
12 | 71b8730b9273 |
13 | 2c7cc79c5810 |
14 | 145926b9ad71 |
15 | 9371c2a63c6 |
hex | 4d7755ba937 |
5323433421111 has 16 divisors (see below), whose sum is σ = 7689676291584. Its totient is φ = 3256342503264.
The previous prime is 5323433421101. The next prime is 5323433421121. The reversal of 5323433421111 is 1111243343235.
It is an interprime number because it is at equal distance from previous prime (5323433421101) and next prime (5323433421121).
It is not a de Polignac number, because 5323433421111 - 25 = 5323433421079 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5323433421101) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 408671011 + ... + 408684036.
It is an arithmetic number, because the mean of its divisors is an integer number (480604768224).
Almost surely, 25323433421111 is an apocalyptic number.
5323433421111 is a deficient number, since it is larger than the sum of its proper divisors (2366242870473).
5323433421111 is a wasteful number, since it uses less digits than its factorization.
5323433421111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 817355230.
The product of its digits is 25920, while the sum is 33.
Adding to 5323433421111 its reverse (1111243343235), we get a palindrome (6434676764346).
The spelling of 5323433421111 in words is "five trillion, three hundred twenty-three billion, four hundred thirty-three million, four hundred twenty-one thousand, one hundred eleven".
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