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532352400133 = 3671450551499
BaseRepresentation
bin1111011111100101010…
…11001111101100000101
31212220002112221220221111
413233302223033230011
532210224203301013
61044320451245021
753314121511541
oct7576253175405
91786075856844
10532352400133
11195851062574
128720b8a9771
133b27b9a39c8
141baa1c5aa21
15dcab02e73d
hex7bf2acfb05

532352400133 has 4 divisors (see below), whose sum is σ = 533802952000. Its totient is φ = 530901848268.

The previous prime is 532352400103. The next prime is 532352400149. The reversal of 532352400133 is 331004253235.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 532352400133 - 213 = 532352391941 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 532352400095 and 532352400104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (532352400103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 725275383 + ... + 725276116.

It is an arithmetic number, because the mean of its divisors is an integer number (133450738000).

Almost surely, 2532352400133 is an apocalyptic number.

It is an amenable number.

532352400133 is a deficient number, since it is larger than the sum of its proper divisors (1450551867).

532352400133 is a wasteful number, since it uses less digits than its factorization.

532352400133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1450551866.

The product of its (nonzero) digits is 32400, while the sum is 31.

Adding to 532352400133 its reverse (331004253235), we get a palindrome (863356653368).

The spelling of 532352400133 in words is "five hundred thirty-two billion, three hundred fifty-two million, four hundred thousand, one hundred thirty-three".

Divisors: 1 367 1450551499 532352400133