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53241241433 = 291835904877
BaseRepresentation
bin110001100101011011…
…001101111101011001
312002102110210021222212
4301211123031331121
51333014224211213
640243024324505
73563240041142
oct614533157531
9162373707885
1053241241433
1120641324786
12a39a473735
13503641b173
142810db2ac9
1515b91dc9a8
hexc656cdf59

53241241433 has 4 divisors (see below), whose sum is σ = 55077146340. Its totient is φ = 51405336528.

The previous prime is 53241241421. The next prime is 53241241439. The reversal of 53241241433 is 33414214235.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 21943385689 + 31297855744 = 148133^2 + 176912^2 .

It is a cyclic number.

It is not a de Polignac number, because 53241241433 - 212 = 53241237337 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 53241241433.

It is not an unprimeable number, because it can be changed into a prime (53241241439) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 917952410 + ... + 917952467.

It is an arithmetic number, because the mean of its divisors is an integer number (13769286585).

Almost surely, 253241241433 is an apocalyptic number.

It is an amenable number.

53241241433 is a deficient number, since it is larger than the sum of its proper divisors (1835904907).

53241241433 is a wasteful number, since it uses less digits than its factorization.

53241241433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1835904906.

The product of its digits is 34560, while the sum is 32.

Adding to 53241241433 its reverse (33414214235), we get a palindrome (86655455668).

The spelling of 53241241433 in words is "fifty-three billion, two hundred forty-one million, two hundred forty-one thousand, four hundred thirty-three".

Divisors: 1 29 1835904877 53241241433