53241243311 has 4 divisors (see below), whose sum is σ = 53256291000. Its totient is φ = 53226195624.

The previous prime is 53241243283. The next prime is 53241243337. The reversal of 53241243311 is 11334214235.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-53241243311 is a prime.

It is a super-2 number, since 2×53241243311² (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53241243361) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7518536 + ... + 7525613.

It is an arithmetic number, because the mean of its divisors is an integer number (13314072750).

Almost surely, 2^53241243311 is an apocalyptic number.

53241243311 is a deficient number, since it is larger than the sum of its proper divisors (15047689).

53241243311 is a wasteful number, since it uses less digits than its factorization.

53241243311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15047688.

The product of its digits is 8640, while the sum is 29.

Adding to 53241243311 its reverse (11334214235), we get a palindrome (64575457546).

The spelling of 53241243311 in words is "fifty-three billion, two hundred forty-one million, two hundred forty-three thousand, three hundred eleven".