Base | Representation |
---|---|
bin | 11000001101100001101111… |
… | …11001100101111010100011 |
3 | 20222111211020101122010011202 |
4 | 30012300313321211322203 |
5 | 23434301242211224403 |
6 | 305122423433231415 |
7 | 14133363226545140 |
oct | 1406606771457243 |
9 | 228454211563152 |
10 | 53241352445603 |
11 | 15a67592502443 |
12 | 5b7a64526256b |
13 | 239283a892b6a |
14 | d20c766433c7 |
15 | 624de2e0e688 |
hex | 306c37e65ea3 |
53241352445603 has 4 divisors (see below), whose sum is σ = 60847259937840. Its totient is φ = 45635444953368.
The previous prime is 53241352445591. The next prime is 53241352445623. The reversal of 53241352445603 is 30654425314235.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 53241352445603 - 24 = 53241352445587 is a prime.
It is a super-2 number, since 2×532413524456032 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (53241352445623) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3802953746108 + ... + 3802953746121.
It is an arithmetic number, because the mean of its divisors is an integer number (15211814984460).
Almost surely, 253241352445603 is an apocalyptic number.
53241352445603 is a deficient number, since it is larger than the sum of its proper divisors (7605907492237).
53241352445603 is an equidigital number, since it uses as much as digits as its factorization.
53241352445603 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7605907492236.
The product of its (nonzero) digits is 5184000, while the sum is 47.
Adding to 53241352445603 its reverse (30654425314235), we get a palindrome (83895777759838).
The spelling of 53241352445603 in words is "fifty-three trillion, two hundred forty-one billion, three hundred fifty-two million, four hundred forty-five thousand, six hundred three".
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