53241543513403 has 4 divisors (see below), whose sum is σ = 60847478301040. Its totient is φ = 45635608725768.

The previous prime is 53241543513401. The next prime is 53241543513451. The reversal of 53241543513403 is 30431534514235.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 53241543513403 - 2¹ = 53241543513401 is a prime.

It is a super-3 number, since 3×53241543513403³ (a number of 42 digits) contains 333 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 53241543513403.

It is not an unprimeable number, because it can be changed into a prime (53241543513401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3802967393808 + ... + 3802967393821.

It is an arithmetic number, because the mean of its divisors is an integer number (15211869575260).

Almost surely, 2^{53241543513403} is an apocalyptic number.

53241543513403 is a deficient number, since it is larger than the sum of its proper divisors (7605934787637).

53241543513403 is an equidigital number, since it uses as much as digits as its factorization.

53241543513403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7605934787636.

The product of its (nonzero) digits is 1296000, while the sum is 43.

The spelling of 53241543513403 in words is "fifty-three trillion, two hundred forty-one billion, five hundred forty-three million, five hundred thirteen thousand, four hundred three".