Base | Representation |
---|---|
bin | 11000001101100010000110… |
… | …10010011101010100111010 |
3 | 20222111211201201011100220220 |
4 | 30012301003102131110322 |
5 | 23434302140114412102 |
6 | 305122454420400510 |
7 | 14133401036601126 |
oct | 1406610322352472 |
9 | 228454651140826 |
10 | 53241543513402 |
11 | 15a67680344512 |
12 | 5b7a699246136 |
13 | 239286b34062a |
14 | d20c93b7c586 |
15 | 624e04aa21bc |
hex | 306c4349d53a |
53241543513402 has 16 divisors (see below), whose sum is σ = 111112786463040. Its totient is φ = 16975564598432.
The previous prime is 53241543513401. The next prime is 53241543513451. The reversal of 53241543513402 is 20431534514235.
It is a super-3 number, since 3×532415435134023 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not an unprimeable number, because it can be changed into a prime (53241543513401) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 192904143027 + ... + 192904143302.
It is an arithmetic number, because the mean of its divisors is an integer number (6944549153940).
Almost surely, 253241543513402 is an apocalyptic number.
53241543513402 is an abundant number, since it is smaller than the sum of its proper divisors (57871242949638).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53241543513402 is a wasteful number, since it uses less digits than its factorization.
53241543513402 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 385808286357.
The product of its (nonzero) digits is 864000, while the sum is 42.
The spelling of 53241543513402 in words is "fifty-three trillion, two hundred forty-one billion, five hundred forty-three million, five hundred thirteen thousand, four hundred two".
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