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532430411341 = 2011264759031
BaseRepresentation
bin1111011111101110101…
…00110101011001001101
31212220021222202022012111
413233313110311121031
532210404141130331
61044332315304021
753316056552503
oct7576724653115
91786258668174
10532430411341
111958910a5544
1287231a4b011
133b291bb8a9a
141baac366673
15dcb2cdddb1
hex7bf753564d

532430411341 has 4 divisors (see below), whose sum is σ = 532695172384. Its totient is φ = 532165650300.

The previous prime is 532430411323. The next prime is 532430411347. The reversal of 532430411341 is 143114034235.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 532430411341 - 25 = 532430411309 is a prime.

It is a super-2 number, since 2×5324304113412 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (532430411347) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 132377505 + ... + 132381526.

It is an arithmetic number, because the mean of its divisors is an integer number (133173793096).

Almost surely, 2532430411341 is an apocalyptic number.

It is an amenable number.

532430411341 is a deficient number, since it is larger than the sum of its proper divisors (264761043).

532430411341 is a wasteful number, since it uses less digits than its factorization.

532430411341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 264761042.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 532430411341 its reverse (143114034235), we get a palindrome (675544445576).

The spelling of 532430411341 in words is "five hundred thirty-two billion, four hundred thirty million, four hundred eleven thousand, three hundred forty-one".

Divisors: 1 2011 264759031 532430411341