Base | Representation |
---|---|
bin | 110001100101100110… |
… | …001010101010001111 |
3 | 12002102200012002222202 |
4 | 301211212022222033 |
5 | 1333020443032003 |
6 | 40243210032115 |
7 | 3563303323532 |
oct | 614546125217 |
9 | 162380162882 |
10 | 53244111503 |
11 | 20642a05040 |
12 | a39b41863b |
13 | 5036bb462b |
14 | 281151ca19 |
15 | 15b95a8088 |
hex | c6598aa8f |
53244111503 has 16 divisors (see below), whose sum is σ = 61634151936. Its totient is φ = 45457991040.
The previous prime is 53244111497. The next prime is 53244111551. The reversal of 53244111503 is 30511144235.
53244111503 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 53244111503 - 212 = 53244107407 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53244111553) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 220901 + ... + 394062.
It is an arithmetic number, because the mean of its divisors is an integer number (3852134496).
Almost surely, 253244111503 is an apocalyptic number.
53244111503 is a deficient number, since it is larger than the sum of its proper divisors (8390040433).
53244111503 is a wasteful number, since it uses less digits than its factorization.
53244111503 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 615454.
The product of its (nonzero) digits is 7200, while the sum is 29.
Adding to 53244111503 its reverse (30511144235), we get a palindrome (83755255738).
The spelling of 53244111503 in words is "fifty-three billion, two hundred forty-four million, one hundred eleven thousand, five hundred three".
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