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53250253625433 = 355313209199881
BaseRepresentation
bin11000001101110010010100…
…11100111001100001011001
320222112200012201202220101210
430012321022130321201121
523434423004412003213
6305130455004333333
714134126632406554
oct1406711234714131
9228480181686353
1053250253625433
1115a7033aa38607
125b8030a244249
132393628a23687
14d2147c89369b
156252645bb0c3
hex306e4a739859

53250253625433 has 8 divisors (see below), whose sum is σ = 71013174988896. Its totient is φ = 35493750672800.

The previous prime is 53250253625381. The next prime is 53250253625473. The reversal of 53250253625433 is 33452635205235.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-53250253625433 is a prime.

It is a super-2 number, since 2×532502536254332 (a number of 28 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (53250253625473) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1604583348 + ... + 1604616533.

It is an arithmetic number, because the mean of its divisors is an integer number (8876646873612).

Almost surely, 253250253625433 is an apocalyptic number.

It is an amenable number.

53250253625433 is a deficient number, since it is larger than the sum of its proper divisors (17762921363463).

53250253625433 is a wasteful number, since it uses less digits than its factorization.

53250253625433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3209205415.

The product of its (nonzero) digits is 9720000, while the sum is 48.

The spelling of 53250253625433 in words is "fifty-three trillion, two hundred fifty billion, two hundred fifty-three million, six hundred twenty-five thousand, four hundred thirty-three".

Divisors: 1 3 5531 16593 3209199881 9627599643 17750084541811 53250253625433