Base | Representation |
---|---|
bin | 11000001101110010010100… |
… | …11100111001100001011001 |
3 | 20222112200012201202220101210 |
4 | 30012321022130321201121 |
5 | 23434423004412003213 |
6 | 305130455004333333 |
7 | 14134126632406554 |
oct | 1406711234714131 |
9 | 228480181686353 |
10 | 53250253625433 |
11 | 15a7033aa38607 |
12 | 5b8030a244249 |
13 | 2393628a23687 |
14 | d2147c89369b |
15 | 6252645bb0c3 |
hex | 306e4a739859 |
53250253625433 has 8 divisors (see below), whose sum is σ = 71013174988896. Its totient is φ = 35493750672800.
The previous prime is 53250253625381. The next prime is 53250253625473. The reversal of 53250253625433 is 33452635205235.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53250253625433 is a prime.
It is a super-2 number, since 2×532502536254332 (a number of 28 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (53250253625473) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1604583348 + ... + 1604616533.
It is an arithmetic number, because the mean of its divisors is an integer number (8876646873612).
Almost surely, 253250253625433 is an apocalyptic number.
It is an amenable number.
53250253625433 is a deficient number, since it is larger than the sum of its proper divisors (17762921363463).
53250253625433 is a wasteful number, since it uses less digits than its factorization.
53250253625433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3209205415.
The product of its (nonzero) digits is 9720000, while the sum is 48.
The spelling of 53250253625433 in words is "fifty-three trillion, two hundred fifty billion, two hundred fifty-three million, six hundred twenty-five thousand, four hundred thirty-three".
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