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53250253625473 is a prime number
BaseRepresentation
bin11000001101110010010100…
…11100111001100010000001
320222112200012201202220110021
430012321022130321202001
523434423004412003343
6305130455004333441
714134126632406642
oct1406711234714201
9228480181686407
1053250253625473
1115a7033aa38643
125b8030a244281
132393628a236b8
14d2147c8936c9
156252645bb0ed
hex306e4a739881

53250253625473 has 2 divisors, whose sum is σ = 53250253625474. Its totient is φ = 53250253625472.

The previous prime is 53250253625381. The next prime is 53250253625497. The reversal of 53250253625473 is 37452635205235.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 39062850000784 + 14187403624689 = 6250028^2 + 3766617^2 .

It is a cyclic number.

It is not a de Polignac number, because 53250253625473 - 217 = 53250253494401 is a prime.

It is a super-2 number, since 2×532502536254732 (a number of 28 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 53250253625473.

It is not a weakly prime, because it can be changed into another prime (53250253625773) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26625126812736 + 26625126812737.

It is an arithmetic number, because the mean of its divisors is an integer number (26625126812737).

Almost surely, 253250253625473 is an apocalyptic number.

It is an amenable number.

53250253625473 is a deficient number, since it is larger than the sum of its proper divisors (1).

53250253625473 is an equidigital number, since it uses as much as digits as its factorization.

53250253625473 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 22680000, while the sum is 52.

The spelling of 53250253625473 in words is "fifty-three trillion, two hundred fifty billion, two hundred fifty-three million, six hundred twenty-five thousand, four hundred seventy-three".