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53251214331 = 372535772111
BaseRepresentation
bin110001100110000001…
…010000101111111011
312002110011112222020110
4301212001100233323
51333024302324311
640244022155403
73563420565510
oct614601205773
9162404488213
1053251214331
1120646a16547
12a3a1882b63
1350385005a3
14281244b307
1515ba00c8a6
hexc66050bfb

53251214331 has 8 divisors (see below), whose sum is σ = 81144707584. Its totient is φ = 30429265320.

The previous prime is 53251214323. The next prime is 53251214353. The reversal of 53251214331 is 13341215235.

53251214331 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 53251214331 - 23 = 53251214323 is a prime.

It is a super-2 number, since 2×532512143312 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (53251214311) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1267886035 + ... + 1267886076.

It is an arithmetic number, because the mean of its divisors is an integer number (10143088448).

Almost surely, 253251214331 is an apocalyptic number.

53251214331 is a deficient number, since it is larger than the sum of its proper divisors (27893493253).

53251214331 is a wasteful number, since it uses less digits than its factorization.

53251214331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2535772121.

The product of its digits is 10800, while the sum is 30.

Adding to 53251214331 its reverse (13341215235), we get a palindrome (66592429566).

The spelling of 53251214331 in words is "fifty-three billion, two hundred fifty-one million, two hundred fourteen thousand, three hundred thirty-one".

Divisors: 1 3 7 21 2535772111 7607316333 17750404777 53251214331