Base | Representation |
---|---|
bin | 110001100110001000… |
… | …000100101111001111 |
3 | 12002110021220200220122 |
4 | 301212020010233033 |
5 | 1333030232001033 |
6 | 40244124335155 |
7 | 3563442014120 |
oct | 614610045717 |
9 | 162407820818 |
10 | 53253000143 |
11 | 20647a26222 |
12 | a3a23a44bb |
13 | 50389a7395 |
14 | 2812794047 |
15 | 15ba261a98 |
hex | c66204bcf |
53253000143 has 4 divisors (see below), whose sum is σ = 60860571600. Its totient is φ = 45645428688.
The previous prime is 53253000133. The next prime is 53253000149. The reversal of 53253000143 is 34100035235.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 53253000143 - 26 = 53253000079 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53253000149) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3803785718 + ... + 3803785731.
It is an arithmetic number, because the mean of its divisors is an integer number (15215142900).
Almost surely, 253253000143 is an apocalyptic number.
53253000143 is a deficient number, since it is larger than the sum of its proper divisors (7607571457).
53253000143 is an equidigital number, since it uses as much as digits as its factorization.
53253000143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7607571456.
The product of its (nonzero) digits is 5400, while the sum is 26.
Adding to 53253000143 its reverse (34100035235), we get a palindrome (87353035378).
The spelling of 53253000143 in words is "fifty-three billion, two hundred fifty-three million, one hundred forty-three", and thus it is an aban number.
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •