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53253082807 = 373142769659
BaseRepresentation
bin110001100110001000…
…011000111010110111
312002110022001220022021
4301212020120322313
51333030242122212
640244130214011
73563442510121
oct614610307267
9162408056267
1053253082807
1120647a82341
12a3a2424307
135038a05bb2
1428127b6211
1515ba27b307
hexc66218eb7

53253082807 has 4 divisors (see below), whose sum is σ = 53395852840. Its totient is φ = 53110312776.

The previous prime is 53253082783. The next prime is 53253082889. The reversal of 53253082807 is 70828035235.

53253082807 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 53253082807 - 27 = 53253082679 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53253086807) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 71384457 + ... + 71385202.

It is an arithmetic number, because the mean of its divisors is an integer number (13348963210).

Almost surely, 253253082807 is an apocalyptic number.

53253082807 is a deficient number, since it is larger than the sum of its proper divisors (142770033).

53253082807 is a wasteful number, since it uses less digits than its factorization.

53253082807 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 142770032.

The product of its (nonzero) digits is 403200, while the sum is 43.

The spelling of 53253082807 in words is "fifty-three billion, two hundred fifty-three million, eighty-two thousand, eight hundred seven".

Divisors: 1 373 142769659 53253082807