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53259501607 = 134096884739
BaseRepresentation
bin110001100110100000…
…111000000000100111
312002110202011000020121
4301212200320000213
51333033413022412
640244515542411
73563551202614
oct614640700047
9162422130217
1053259501607
1120650666934
12a3a45baa07
13503a1426c0
1428135a750b
1515baae8107
hexc66838027

53259501607 has 4 divisors (see below), whose sum is σ = 57356386360. Its totient is φ = 49162616856.

The previous prime is 53259501577. The next prime is 53259501641. The reversal of 53259501607 is 70610595235.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-53259501607 is a prime.

It is a super-2 number, since 2×532595016072 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53259501697) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2048442357 + ... + 2048442382.

It is an arithmetic number, because the mean of its divisors is an integer number (14339096590).

Almost surely, 253259501607 is an apocalyptic number.

53259501607 is a deficient number, since it is larger than the sum of its proper divisors (4096884753).

53259501607 is a wasteful number, since it uses less digits than its factorization.

53259501607 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4096884752.

The product of its (nonzero) digits is 283500, while the sum is 43.

The spelling of 53259501607 in words is "fifty-three billion, two hundred fifty-nine million, five hundred one thousand, six hundred seven".

Divisors: 1 13 4096884739 53259501607