Base | Representation |
---|---|

bin | 11000001110000101100111… |

… | …01100001001110100001011 |

3 | 20222120122221102112220022122 |

4 | 30013002303230021310023 |

5 | 23440110211421312403 |

6 | 305135330331441455 |

7 | 14134644355144646 |

oct | 1407026354116413 |

9 | 228518842486278 |

10 | 53260609166603 |

11 | 15a747744119a3 |

12 | 5b8231a2b628b |

13 | 23945b9287227 |

14 | d21b81d26a5d |

15 | 62566d7a9838 |

hex | 3070b3b09d0b |

53260609166603 has 4 divisors (see below), whose sum is σ = 56063799122760. Its totient is φ = 50457419210448.

The previous prime is 53260609166599. The next prime is 53260609166621. The reversal of 53260609166603 is 30666190606235.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 53260609166603 - 2^{2} = 53260609166599 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (53260609166623) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1401594978050 + ... + 1401594978087.

It is an arithmetic number, because the mean of its divisors is an integer number (14015949780690).

Almost surely, 2^{53260609166603} is an apocalyptic number.

53260609166603 is a deficient number, since it is larger than the sum of its proper divisors (2803189956157).

53260609166603 is a wasteful number, since it uses less digits than its factorization.

53260609166603 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2803189956156.

The product of its (nonzero) digits is 6298560, while the sum is 53.

The spelling of 53260609166603 in words is "fifty-three trillion, two hundred sixty billion, six hundred nine million, one hundred sixty-six thousand, six hundred three".

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