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53261795513 = 76696945077
BaseRepresentation
bin110001100110101001…
…101000000010111001
312002110220110112220002
4301212221220002321
51333040004424023
640245041042345
73563606535443
oct614651500271
9162426415802
1053261795513
1120651993323
12a3a53263b5
13503a766844
142813a03493
1515badecb28
hexc66a680b9

53261795513 has 4 divisors (see below), whose sum is σ = 53268748260. Its totient is φ = 53254842768.

The previous prime is 53261795491. The next prime is 53261795557. The reversal of 53261795513 is 31559716235.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 43215341689 + 10046453824 = 207883^2 + 100232^2 .

It is a cyclic number.

It is not a de Polignac number, because 53261795513 - 220 = 53260746937 is a prime.

It is a super-3 number, since 3×532617955133 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (53261705513) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3464870 + ... + 3480207.

It is an arithmetic number, because the mean of its divisors is an integer number (13317187065).

Almost surely, 253261795513 is an apocalyptic number.

It is an amenable number.

53261795513 is a deficient number, since it is larger than the sum of its proper divisors (6952747).

53261795513 is an equidigital number, since it uses as much as digits as its factorization.

53261795513 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6952746.

The product of its digits is 850500, while the sum is 47.

The spelling of 53261795513 in words is "fifty-three billion, two hundred sixty-one million, seven hundred ninety-five thousand, five hundred thirteen".

Divisors: 1 7669 6945077 53261795513