Base | Representation |
---|---|
bin | 11000001110001011000010… |
… | …00010100011011011011111 |
3 | 20222120221110010002101200022 |
4 | 30013011201002203123133 |
5 | 23440132140434401210 |
6 | 305140531103222355 |
7 | 14135106421432325 |
oct | 1407054102433337 |
9 | 228527403071608 |
10 | 53263517497055 |
11 | 15a75a27060688 |
12 | 5b829b02a79bb |
13 | 2394960983918 |
14 | d21d7a2a9d15 |
15 | 62578dc92155 |
hex | 3071610a36df |
53263517497055 has 8 divisors (see below), whose sum is σ = 65475153216144. Its totient is φ = 41571525851200.
The previous prime is 53263517497007. The next prime is 53263517497067. The reversal of 53263517497055 is 55079471536235.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 53263517497055 - 214 = 53263517480671 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 129911018081 + ... + 129911018490.
It is an arithmetic number, because the mean of its divisors is an integer number (8184394152018).
Almost surely, 253263517497055 is an apocalyptic number.
53263517497055 is a deficient number, since it is larger than the sum of its proper divisors (12211635719089).
53263517497055 is a wasteful number, since it uses less digits than its factorization.
53263517497055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 259822036617.
The product of its (nonzero) digits is 119070000, while the sum is 62.
The spelling of 53263517497055 in words is "fifty-three trillion, two hundred sixty-three billion, five hundred seventeen million, four hundred ninety-seven thousand, fifty-five".
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