Base | Representation |
---|---|
bin | 110001101000100100… |
… | …011101000111000001 |
3 | 12002120011001102111200 |
4 | 301220210131013001 |
5 | 1333121230310213 |
6 | 40252151131413 |
7 | 3564450323031 |
oct | 615044350701 |
9 | 162504042450 |
10 | 53293994433 |
11 | 206690858a9 |
12 | a3b4073b69 |
13 | 504432b664 |
14 | 2817dc58c1 |
15 | 15bdb5d273 |
hex | c6891d1c1 |
53293994433 has 24 divisors (see below), whose sum is σ = 81517363200. Its totient is φ = 33435717504.
The previous prime is 53293994407. The next prime is 53293994471. The reversal of 53293994433 is 33449939235.
53293994433 is a `hidden beast` number, since 5 + 32 + 93 + 9 + 94 + 433 = 666.
It is not a de Polignac number, because 53293994433 - 25 = 53293994401 is a prime.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 53293994433.
It is not an unprimeable number, because it can be changed into a prime (53293994333) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2338588 + ... + 2361266.
It is an arithmetic number, because the mean of its divisors is an integer number (3396556800).
Almost surely, 253293994433 is an apocalyptic number.
It is an amenable number.
53293994433 is a deficient number, since it is larger than the sum of its proper divisors (28223368767).
53293994433 is a wasteful number, since it uses less digits than its factorization.
53293994433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 38061 (or 38058 counting only the distinct ones).
The product of its digits is 9447840, while the sum is 54.
The spelling of 53293994433 in words is "fifty-three billion, two hundred ninety-three million, nine hundred ninety-four thousand, four hundred thirty-three".
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