5329433 has 4 divisors (see below), whose sum is σ = 5334528. Its totient is φ = 5324340.

The previous prime is 5329397. The next prime is 5329453. The reversal of 5329433 is 3349235.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 3349235 = 5 ⋅669847.

It is a cyclic number.

It is not a de Polignac number, because 5329433 - 2¹⁰ = 5328409 is a prime.

It is a super-2 number, since 2×5329433² = 56805712202978, which contains 22 as substring.

It is a d-powerful number, because it can be written as 5 + 3⁸ + 2¹³ + 9 + 4⁴ + 3¹² + 3¹⁴ .

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5329396 and 5329405.

It is not an unprimeable number, because it can be changed into a prime (5329453) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 341 + ... + 3282.

It is an arithmetic number, because the mean of its divisors is an integer number (1333632).

Almost surely, 2^5329433 is an apocalyptic number.

It is an amenable number.

5329433 is a deficient number, since it is larger than the sum of its proper divisors (5095).

5329433 is a wasteful number, since it uses less digits than its factorization.

5329433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5094.

The product of its digits is 9720, while the sum is 29.

The square root of 5329433 is about 2308.5564753759. The cubic root of 5329433 is about 174.6734918731.

The spelling of 5329433 in words is "five million, three hundred twenty-nine thousand, four hundred thirty-three".