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5330040555311 = 5990339670429
BaseRepresentation
bin100110110001111111100…
…1011001000011100101111
3200212112202200122110221222
41031203333023020130233
51144311410340232221
615200330431013555
71060040242123433
oct115437713103457
920775680573858
105330040555311
111775503a3767a
12720bb796a2bb
132c880b7b7494
14145d9248c9c3
15939a736a9ab
hex4d8ff2c872f

5330040555311 has 4 divisors (see below), whose sum is σ = 5420380225800. Its totient is φ = 5239700884824.

The previous prime is 5330040555299. The next prime is 5330040555347. The reversal of 5330040555311 is 1135550400335.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5330040555311 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5330040555211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 45169835156 + ... + 45169835273.

It is an arithmetic number, because the mean of its divisors is an integer number (1355095056450).

Almost surely, 25330040555311 is an apocalyptic number.

5330040555311 is a deficient number, since it is larger than the sum of its proper divisors (90339670489).

5330040555311 is an equidigital number, since it uses as much as digits as its factorization.

5330040555311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 90339670488.

The product of its (nonzero) digits is 67500, while the sum is 35.

Adding to 5330040555311 its reverse (1135550400335), we get a palindrome (6465590955646).

The spelling of 5330040555311 in words is "five trillion, three hundred thirty billion, forty million, five hundred fifty-five thousand, three hundred eleven".

Divisors: 1 59 90339670429 5330040555311