Base | Representation |
---|---|
bin | 100110110010111101011… |
… | …0001011101011101110011 |
3 | 200212202010012120120022020 |
4 | 1031211322301131131303 |
5 | 1144330132213403220 |
6 | 15201312304242523 |
7 | 1060142521613151 |
oct | 115457261353563 |
9 | 20782105516266 |
10 | 5332114200435 |
11 | 1776378504980 |
12 | 721496310443 |
13 | 2c8a7c2a8529 |
14 | 14610ba383d1 |
15 | 93a79429040 |
hex | 4d97ac5d773 |
5332114200435 has 32 divisors (see below), whose sum is σ = 9607187589120. Its totient is φ = 2501871763200.
The previous prime is 5332114200431. The next prime is 5332114200461. The reversal of 5332114200435 is 5340024112335.
It is not a de Polignac number, because 5332114200435 - 22 = 5332114200431 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (33).
It is a junction number, because it is equal to n+sod(n) for n = 5332114200396 and 5332114200405.
It is not an unprimeable number, because it can be changed into a prime (5332114200431) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 521218170 + ... + 521228399.
It is an arithmetic number, because the mean of its divisors is an integer number (300224612160).
Almost surely, 25332114200435 is an apocalyptic number.
5332114200435 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
5332114200435 is a deficient number, since it is larger than the sum of its proper divisors (4275073388685).
5332114200435 is a wasteful number, since it uses less digits than its factorization.
5332114200435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1042446619.
The product of its (nonzero) digits is 43200, while the sum is 33.
The spelling of 5332114200435 in words is "five trillion, three hundred thirty-two billion, one hundred fourteen million, two hundred thousand, four hundred thirty-five".
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