Base | Representation |
---|---|
bin | 1111100001001111011… |
… | …01010011001001011011 |
3 | 1212222101120010221021212 |
4 | 13300213231103021123 |
5 | 32214034441143120 |
6 | 1044545033253335 |
7 | 53345144220305 |
oct | 7604755231133 |
9 | 1788346127255 |
10 | 533242131035 |
11 | 196168310569 |
12 | 8741986424b |
13 | 3b3911131b3 |
14 | 1bb480a2975 |
15 | dd0e1cd6c5 |
hex | 7c27b5325b |
533242131035 has 16 divisors (see below), whose sum is σ = 656901397152. Its totient is φ = 415297708800.
The previous prime is 533242131031. The next prime is 533242131119. The reversal of 533242131035 is 530131242335.
It is not a de Polignac number, because 533242131035 - 22 = 533242131031 is a prime.
It is a super-2 number, since 2×5332421310352 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 533242130992 and 533242131010.
It is not an unprimeable number, because it can be changed into a prime (533242131031) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2689256 + ... + 2880725.
It is an arithmetic number, because the mean of its divisors is an integer number (41056337322).
Almost surely, 2533242131035 is an apocalyptic number.
533242131035 is a deficient number, since it is larger than the sum of its proper divisors (123659266117).
533242131035 is a wasteful number, since it uses less digits than its factorization.
533242131035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5570494.
The product of its (nonzero) digits is 32400, while the sum is 32.
The spelling of 533242131035 in words is "five hundred thirty-three billion, two hundred forty-two million, one hundred thirty-one thousand, thirty-five".
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