Base | Representation |
---|---|
bin | 100110110011100000110… |
… | …0100110110001110101101 |
3 | 200212212011222202220200212 |
4 | 1031213001210312032231 |
5 | 1144340100312420313 |
6 | 15202030220432205 |
7 | 1060214124444200 |
oct | 115470144661655 |
9 | 20785158686625 |
10 | 5333302076333 |
11 | 1776927a8a6a0 |
12 | 7217680a8665 |
13 | 2c8c0b41638a |
14 | 1461c16cd937 |
15 | 93ae886c3a8 |
hex | 4d9c19363ad |
5333302076333 has 72 divisors (see below), whose sum is σ = 7491295990080. Its totient is φ = 3741297288960.
The previous prime is 5333302076317. The next prime is 5333302076371. The reversal of 5333302076333 is 3336702033335.
It is not a de Polignac number, because 5333302076333 - 24 = 5333302076317 is a prime.
It is a super-2 number, since 2×53333020763332 (a number of 26 digits) contains 22 as substring.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5333302076633) by changing a digit.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 4297088 + ... + 5397366.
It is an arithmetic number, because the mean of its divisors is an integer number (104045777640).
Almost surely, 25333302076333 is an apocalyptic number.
It is an amenable number.
5333302076333 is a deficient number, since it is larger than the sum of its proper divisors (2157993913747).
5333302076333 is a wasteful number, since it uses less digits than its factorization.
5333302076333 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1100367 (or 1100337 counting only the distinct ones).
The product of its (nonzero) digits is 918540, while the sum is 41.
The spelling of 5333302076333 in words is "five trillion, three hundred thirty-three billion, three hundred two million, seventy-six thousand, three hundred thirty-three".
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