Base | Representation |
---|---|
bin | 111100101000100100101110… |
… | …0011101000010110000000001 |
3 | 2120221101222220222212202211110 |
4 | 1321101021130131002300001 |
5 | 1024401233404000000001 |
6 | 5130153533215233533 |
7 | 220224454645006263 |
oct | 17121113435026001 |
9 | 2527358828782743 |
10 | 533342000000001 |
11 | 144a370878914a5 |
12 | 4b9993048188a9 |
13 | 19b79c1c98b32a |
14 | 959bc678a7b33 |
15 | 419d6b19743d6 |
hex | 1e5125c742c01 |
533342000000001 has 4 divisors (see below), whose sum is σ = 711122666666672. Its totient is φ = 355561333333332.
The previous prime is 533341999999981. The next prime is 533342000000057. The reversal of 533342000000001 is 100000000243335.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 533342000000001 - 26 = 533341999999937 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (533342000000081) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 88890333333331 + ... + 88890333333336.
It is an arithmetic number, because the mean of its divisors is an integer number (177780666666668).
Almost surely, 2533342000000001 is an apocalyptic number.
It is an amenable number.
533342000000001 is a deficient number, since it is larger than the sum of its proper divisors (177780666666671).
533342000000001 is a wasteful number, since it uses less digits than its factorization.
533342000000001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 177780666666670.
The product of its (nonzero) digits is 1080, while the sum is 21.
Adding to 533342000000001 its reverse (100000000243335), we get a palindrome (633342000243336).
The spelling of 533342000000001 in words is "five hundred thirty-three trillion, three hundred forty-two billion, one", and thus it is an aban number.
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