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533341999999981 is a prime number
BaseRepresentation
bin111100101000100100101110…
…0011101000010101111101101
32120221101222220222212202210201
41321101021130131002233231
51024401233403444444411
65130153533215233501
7220224454645006234
oct17121113435025755
92527358828782721
10533341999999981
11144a37087891487
124b999304818891
1319b79c1c98b313
14959bc678a7b1b
15419d6b19743c1
hex1e5125c742bed

533341999999981 has 2 divisors, whose sum is σ = 533341999999982. Its totient is φ = 533341999999980.

The previous prime is 533341999999967. The next prime is 533342000000057. The reversal of 533341999999981 is 189999999143335.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 306232850240100 + 227109149759881 = 17499510^2 + 15070141^2 .

It is a cyclic number.

It is not a de Polignac number, because 533341999999981 - 29 = 533341999999469 is a prime.

It is a super-2 number, since 2×5333419999999812 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (533341999999961) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 266670999999990 + 266670999999991.

It is an arithmetic number, because the mean of its divisors is an integer number (266670999999991).

Almost surely, 2533341999999981 is an apocalyptic number.

It is an amenable number.

533341999999981 is a deficient number, since it is larger than the sum of its proper divisors (1).

533341999999981 is an equidigital number, since it uses as much as digits as its factorization.

533341999999981 is an evil number, because the sum of its binary digits is even.

The product of its digits is 20662426080, while the sum is 91.

The spelling of 533341999999981 in words is "five hundred thirty-three trillion, three hundred forty-one billion, nine hundred ninety-nine million, nine hundred ninety-nine thousand, nine hundred eighty-one".