Base | Representation |
---|---|
bin | 110001101011010101… |
… | …101000010111101100 |
3 | 12002200101110002220111 |
4 | 301223111220113230 |
5 | 1333220123040134 |
6 | 40300530425404 |
7 | 3565553155003 |
oct | 615325502754 |
9 | 162611402814 |
10 | 53340440044 |
11 | 20692319101 |
12 | a407732264 |
13 | 5050b40c78 |
14 | 2820235c3a |
15 | 15c2c84c64 |
hex | c6b5685ec |
53340440044 has 6 divisors (see below), whose sum is σ = 93345770084. Its totient is φ = 26670220020.
The previous prime is 53340440011. The next prime is 53340440071. The reversal of 53340440044 is 44004404335.
It is a junction number, because it is equal to n+sod(n) for n = 53340439988 and 53340440015.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6667555002 + ... + 6667555009.
Almost surely, 253340440044 is an apocalyptic number.
It is an amenable number.
53340440044 is a deficient number, since it is larger than the sum of its proper divisors (40005330040).
53340440044 is a wasteful number, since it uses less digits than its factorization.
53340440044 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13335110015 (or 13335110013 counting only the distinct ones).
The product of its (nonzero) digits is 46080, while the sum is 31.
Adding to 53340440044 its reverse (44004404335), we get a palindrome (97344844379).
The spelling of 53340440044 in words is "fifty-three billion, three hundred forty million, four hundred forty thousand, forty-four".
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