Base | Representation |
---|---|
bin | 100110110100000010000… |
… | …1111010011101010101111 |
3 | 200212222001221021212221201 |
4 | 1031220010033103222233 |
5 | 1144344343122100330 |
6 | 15202333212310331 |
7 | 1060253625065026 |
oct | 115500417235257 |
9 | 20788057255851 |
10 | 5334420503215 |
11 | 1777351340331 |
12 | 721a1a7723a7 |
13 | 2c905904942b |
14 | 14628a0678bd |
15 | 93b61b42eca |
hex | 4da043d3aaf |
5334420503215 has 8 divisors (see below), whose sum is σ = 6401509521840. Its totient is φ = 4267399790592.
The previous prime is 5334420503179. The next prime is 5334420503249. The reversal of 5334420503215 is 5123050244335.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5334420503215 - 227 = 5334286285487 is a prime.
It is a super-3 number, since 3×53344205032153 (a number of 39 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 16904530 + ... + 17217199.
It is an arithmetic number, because the mean of its divisors is an integer number (800188690230).
Almost surely, 25334420503215 is an apocalyptic number.
5334420503215 is a deficient number, since it is larger than the sum of its proper divisors (1067089018625).
5334420503215 is a wasteful number, since it uses less digits than its factorization.
5334420503215 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 34153001.
The product of its (nonzero) digits is 216000, while the sum is 37.
The spelling of 5334420503215 in words is "five trillion, three hundred thirty-four billion, four hundred twenty million, five hundred three thousand, two hundred fifteen".
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