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5334425502121 = 7175132753551
BaseRepresentation
bin100110110100000010010…
…0010011000000110101001
3200212222002021200212011101
41031220010202120012221
51144344400412031441
615202333511401401
71060254015425062
oct115500442300651
920788067625141
105334425502121
111777354145061
12721a20383261
132c905a0a9871
1414628a9a9569
1593b622ce231
hex4da048981a9

5334425502121 has 4 divisors (see below), whose sum is σ = 5409558255744. Its totient is φ = 5259292748500.

The previous prime is 5334425502097. The next prime is 5334425502139. The reversal of 5334425502121 is 1212055244335.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5334425502121 - 211 = 5334425500073 is a prime.

It is a super-5 number, since 5×53344255021215 (a number of 65 digits) contains 55555 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5334425502521) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 37566376705 + ... + 37566376846.

It is an arithmetic number, because the mean of its divisors is an integer number (1352389563936).

Almost surely, 25334425502121 is an apocalyptic number.

It is an amenable number.

5334425502121 is a deficient number, since it is larger than the sum of its proper divisors (75132753623).

5334425502121 is an equidigital number, since it uses as much as digits as its factorization.

5334425502121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 75132753622.

The product of its (nonzero) digits is 144000, while the sum is 37.

The spelling of 5334425502121 in words is "five trillion, three hundred thirty-four billion, four hundred twenty-five million, five hundred two thousand, one hundred twenty-one".

Divisors: 1 71 75132753551 5334425502121