Base | Representation |
---|---|
bin | 11000010000100011110101… |
… | …01001001110010011010001 |
3 | 20222212210012012102122012020 |
4 | 30020101322221032103101 |
5 | 23443003142132140103 |
6 | 305242335155322053 |
7 | 14144042331451044 |
oct | 1410217251162321 |
9 | 228783165378166 |
10 | 53345551443153 |
11 | 15aa77a308a552 |
12 | 5b968852b0329 |
13 | 239c6052b9c28 |
14 | d25d1d218c5b |
15 | 627990acb753 |
hex | 30847aa4e4d1 |
53345551443153 has 32 divisors (see below), whose sum is σ = 73633083847680. Its totient is φ = 34334311717440.
The previous prime is 53345551443143. The next prime is 53345551443241. The reversal of 53345551443153 is 35134415554335.
It is not a de Polignac number, because 53345551443153 - 213 = 53345551434961 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 53345551443096 and 53345551443105.
It is not an unprimeable number, because it can be changed into a prime (53345551443143) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3100500 + ... + 10784442.
It is an arithmetic number, because the mean of its divisors is an integer number (2301033870240).
Almost surely, 253345551443153 is an apocalyptic number.
It is an amenable number.
53345551443153 is a deficient number, since it is larger than the sum of its proper divisors (20287532404527).
53345551443153 is a wasteful number, since it uses less digits than its factorization.
53345551443153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7684709.
The product of its digits is 16200000, while the sum is 51.
Adding to 53345551443153 its reverse (35134415554335), we get a palindrome (88479966997488).
The spelling of 53345551443153 in words is "fifty-three trillion, three hundred forty-five billion, five hundred fifty-one million, four hundred forty-three thousand, one hundred fifty-three".
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