Base | Representation |
---|---|
bin | 110001101011111010… |
… | …101111011100111101 |
3 | 12002201001202100200021 |
4 | 301223322233130331 |
5 | 1333230120342011 |
6 | 40301515132141 |
7 | 3566031643336 |
oct | 615372573475 |
9 | 162631670607 |
10 | 53350168381 |
11 | 20697863154 |
12 | a40aa44051 |
13 | 5052b68c93 |
14 | 282164928d |
15 | 15c3a57471 |
hex | c6beaf73d |
53350168381 has 4 divisors (see below), whose sum is σ = 56158072000. Its totient is φ = 50542264764.
The previous prime is 53350168367. The next prime is 53350168387. The reversal of 53350168381 is 18386105335.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 53350168381 - 215 = 53350135613 is a prime.
It is a super-2 number, since 2×533501683812 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53350168387) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1403951781 + ... + 1403951818.
It is an arithmetic number, because the mean of its divisors is an integer number (14039518000).
Almost surely, 253350168381 is an apocalyptic number.
It is an amenable number.
53350168381 is a deficient number, since it is larger than the sum of its proper divisors (2807903619).
53350168381 is a wasteful number, since it uses less digits than its factorization.
53350168381 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2807903618.
The product of its (nonzero) digits is 259200, while the sum is 43.
The spelling of 53350168381 in words is "fifty-three billion, three hundred fifty million, one hundred sixty-eight thousand, three hundred eighty-one".
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