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53350413101 = 192807916479
BaseRepresentation
bin110001101011111011…
…101011001100101101
312002201002012210100222
4301223323223030231
51333230201204401
640301524301125
73566034012656
oct615373531455
9162632183328
1053350413101
1120697a0aaa7
12a40ab417a5
135052c2349b
1428216b052d
1515c3aa4c1b
hexc6beeb32d

53350413101 has 4 divisors (see below), whose sum is σ = 56158329600. Its totient is φ = 50542496604.

The previous prime is 53350413089. The next prime is 53350413113. The reversal of 53350413101 is 10131405335.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (53350413089) and next prime (53350413113).

It is a cyclic number.

It is not a de Polignac number, because 53350413101 - 214 = 53350396717 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53350418101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1403958221 + ... + 1403958258.

It is an arithmetic number, because the mean of its divisors is an integer number (14039582400).

Almost surely, 253350413101 is an apocalyptic number.

It is an amenable number.

53350413101 is a deficient number, since it is larger than the sum of its proper divisors (2807916499).

53350413101 is a wasteful number, since it uses less digits than its factorization.

53350413101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2807916498.

The product of its (nonzero) digits is 2700, while the sum is 26.

Adding to 53350413101 its reverse (10131405335), we get a palindrome (63481818436).

The spelling of 53350413101 in words is "fifty-three billion, three hundred fifty million, four hundred thirteen thousand, one hundred one".

Divisors: 1 19 2807916479 53350413101