Base | Representation |
---|---|
bin | 100110110100010111111… |
… | …0101110000110110110111 |
3 | 200220000221220202000010012 |
4 | 1031220233311300312313 |
5 | 1144402342403121120 |
6 | 15202533543050435 |
7 | 1060311016536653 |
oct | 115505765606667 |
9 | 20800856660105 |
10 | 5335152004535 |
11 | 1777697246081 |
12 | 721ba3740a1b |
13 | 2c9144767c52 |
14 | 146319281a63 |
15 | 93ba5e891c5 |
hex | 4da2fd70db7 |
5335152004535 has 8 divisors (see below), whose sum is σ = 6778781370576. Its totient is φ = 4017055626880.
The previous prime is 5335152004517. The next prime is 5335152004541. The reversal of 5335152004535 is 5354002515335.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 5335152004535 - 212 = 5335152000439 is a prime.
It is a super-2 number, since 2×53351520045352 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5335152004492 and 5335152004501.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 31383247001 + ... + 31383247170.
It is an arithmetic number, because the mean of its divisors is an integer number (847347671322).
Almost surely, 25335152004535 is an apocalyptic number.
5335152004535 is a deficient number, since it is larger than the sum of its proper divisors (1443629366041).
5335152004535 is a wasteful number, since it uses less digits than its factorization.
5335152004535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 62766494193.
The product of its (nonzero) digits is 675000, while the sum is 41.
The spelling of 5335152004535 in words is "five trillion, three hundred thirty-five billion, one hundred fifty-two million, four thousand, five hundred thirty-five".
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