Base | Representation |
---|---|
bin | 110001101100000101… |
… | …110010101101110111 |
3 | 12002201021012112112212 |
4 | 301230011302231313 |
5 | 1333231341042320 |
6 | 40302101204035 |
7 | 3566065400303 |
oct | 615405625567 |
9 | 162637175485 |
10 | 53353065335 |
11 | 20699461729 |
12 | a40ba0061b |
13 | 505364175b |
14 | 2821ba0d03 |
15 | 15c3e2a9c5 |
hex | c6c172b77 |
53353065335 has 4 divisors (see below), whose sum is σ = 64023678408. Its totient is φ = 42682452264.
The previous prime is 53353065331. The next prime is 53353065347. The reversal of 53353065335 is 53356035335.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 53353065335 - 22 = 53353065331 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 53353065292 and 53353065301.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53353065331) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5335306529 + ... + 5335306538.
It is an arithmetic number, because the mean of its divisors is an integer number (16005919602).
Almost surely, 253353065335 is an apocalyptic number.
53353065335 is a deficient number, since it is larger than the sum of its proper divisors (10670613073).
53353065335 is a wasteful number, since it uses less digits than its factorization.
53353065335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10670613072.
The product of its (nonzero) digits is 911250, while the sum is 41.
The spelling of 53353065335 in words is "fifty-three billion, three hundred fifty-three million, sixty-five thousand, three hundred thirty-five".
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