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5335344100433 = 41673835071133
BaseRepresentation
bin100110110100011101101…
…0010100011010001010001
3200220001110022012111011002
41031220323102203101101
51144403241042203213
615203005004231345
71060315541404214
oct115507322432121
920801408174132
105335344100433
11177778571a616
12722037b3b555
132c91754b5669
141463369a777b
1593bb7c81658
hex4da3b4a3451

5335344100433 has 16 divisors (see below), whose sum is σ = 5561532942336. Its totient is φ = 5114135199360.

The previous prime is 5335344100423. The next prime is 5335344100451. The reversal of 5335344100433 is 3340014435335.

It is a cyclic number.

It is not a de Polignac number, because 5335344100433 - 230 = 5334270358609 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5335344100403) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1483466 + ... + 3587667.

It is an arithmetic number, because the mean of its divisors is an integer number (347595808896).

Almost surely, 25335344100433 is an apocalyptic number.

It is an amenable number.

5335344100433 is a deficient number, since it is larger than the sum of its proper divisors (226188841903).

5335344100433 is a wasteful number, since it uses less digits than its factorization.

5335344100433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5071624.

The product of its (nonzero) digits is 388800, while the sum is 38.

Adding to 5335344100433 its reverse (3340014435335), we get a palindrome (8675358535768).

The spelling of 5335344100433 in words is "five trillion, three hundred thirty-five billion, three hundred forty-four million, one hundred thousand, four hundred thirty-three".

Divisors: 1 41 67 383 2747 15703 25661 1052101 5071133 207916453 339765911 1942243939 13930402351 79632001499 130130343913 5335344100433