Base | Representation |
---|---|
bin | 100110110100011101101… |
… | …1000000001010000110001 |
3 | 200220001110101220022122012 |
4 | 1031220323120001100301 |
5 | 1144403241424042001 |
6 | 15203005055052305 |
7 | 1060315556524550 |
oct | 115507330012061 |
9 | 20801411808565 |
10 | 5335345534001 |
11 | 177778650968a |
12 | 722038511095 |
13 | 2c9175898022 |
14 | 146336c5bd97 |
15 | 93bb7e662bb |
hex | 4da3b601431 |
5335345534001 has 32 divisors (see below), whose sum is σ = 6145412666880. Its totient is φ = 4537417637376.
The previous prime is 5335345533983. The next prime is 5335345534021. The reversal of 5335345534001 is 1004355435335.
It is a de Polignac number, because none of the positive numbers 2k-5335345534001 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 5335345534001.
It is not an unprimeable number, because it can be changed into a prime (5335345534021) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 673055900 + ... + 673063826.
It is an arithmetic number, because the mean of its divisors is an integer number (192044145840).
Almost surely, 25335345534001 is an apocalyptic number.
It is an amenable number.
5335345534001 is a deficient number, since it is larger than the sum of its proper divisors (810067132879).
5335345534001 is a wasteful number, since it uses less digits than its factorization.
5335345534001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9633.
The product of its (nonzero) digits is 810000, while the sum is 41.
The spelling of 5335345534001 in words is "five trillion, three hundred thirty-five billion, three hundred forty-five million, five hundred thirty-four thousand, one".
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