5335400533 has 4 divisors (see below), whose sum is σ = 5335556320. Its totient is φ = 5335244748.

The previous prime is 5335400519. The next prime is 5335400537. The reversal of 5335400533 is 3350045335.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5335400533 - 2²⁵ = 5301846101 is a prime.

It is a super-3 number, since 3×5335400533³ (a number of 30 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5335400495 and 5335400504.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5335400537) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1635 + ... + 103312.

It is an arithmetic number, because the mean of its divisors is an integer number (1333889080).

Almost surely, 2^5335400533 is an apocalyptic number.

It is an amenable number.

5335400533 is a deficient number, since it is larger than the sum of its proper divisors (155787).

5335400533 is a wasteful number, since it uses less digits than its factorization.

5335400533 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 155786.

The product of its (nonzero) digits is 40500, while the sum is 31.

The square root of 5335400533 is about 73043.8261114517. The cubic root of 5335400533 is about 1747.3866334698.

Adding to 5335400533 its reverse (3350045335), we get a palindrome (8685445868).

The spelling of 5335400533 in words is "five billion, three hundred thirty-five million, four hundred thousand, five hundred thirty-three".