Search a number
-
+
533540120331 = 35471116129131
BaseRepresentation
bin1111100001110010111…
…10000010011100001011
31220000011022212100202110
413300321132002130023
532220142232322311
61045034400233403
753355423123621
oct7607136023413
91800138770673
10533540120331
11196300541309
12874a160b863
133b40aa88a1a
141bb758b1511
15dd2a4418a6
hex7c3978270b

533540120331 has 16 divisors (see below), whose sum is σ = 712775673728. Its totient is φ = 354999153600.

The previous prime is 533540120257. The next prime is 533540120363. The reversal of 533540120331 is 133021045335.

It is not a de Polignac number, because 533540120331 - 27 = 533540120203 is a prime.

It is a super-2 number, since 2×5335401203312 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (533540120131) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 18300636 + ... + 18329766.

It is an arithmetic number, because the mean of its divisors is an integer number (44548479608).

Almost surely, 2533540120331 is an apocalyptic number.

533540120331 is a deficient number, since it is larger than the sum of its proper divisors (179235553397).

533540120331 is a wasteful number, since it uses less digits than its factorization.

533540120331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 40842.

The product of its (nonzero) digits is 16200, while the sum is 30.

Adding to 533540120331 its reverse (133021045335), we get a palindrome (666561165666).

The spelling of 533540120331 in words is "five hundred thirty-three billion, five hundred forty million, one hundred twenty thousand, three hundred thirty-one".

Divisors: 1 3 547 1641 11161 29131 33483 87393 6105067 15934657 18315201 47803971 325131091 975393273 177846706777 533540120331