Base | Representation |
---|---|
bin | 110001101100001010… |
… | …101010111010110001 |
3 | 12002201100121111201000 |
4 | 301230022222322301 |
5 | 1333232203002423 |
6 | 40302144432213 |
7 | 3566112304440 |
oct | 615412527261 |
9 | 162640544630 |
10 | 53354344113 |
11 | 2069a155474 |
12 | a410318669 |
13 | 505399b825 |
14 | 2822014d57 |
15 | 15c40ce843 |
hex | c6c2aaeb1 |
53354344113 has 32 divisors (see below), whose sum is σ = 90346161920. Its totient is φ = 30484563840.
The previous prime is 53354344111. The next prime is 53354344129. The reversal of 53354344113 is 31144345335.
53354344113 is a `hidden beast` number, since 533 + 5 + 4 + 3 + 4 + 4 + 113 = 666.
53354344113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 53354344113 - 21 = 53354344111 is a prime.
It is not an unprimeable number, because it can be changed into a prime (53354344111) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3025983 + ... + 3043563.
It is an arithmetic number, because the mean of its divisors is an integer number (2823317560).
Almost surely, 253354344113 is an apocalyptic number.
It is an amenable number.
53354344113 is a deficient number, since it is larger than the sum of its proper divisors (36991817807).
53354344113 is a wasteful number, since it uses less digits than its factorization.
53354344113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 33654 (or 33648 counting only the distinct ones).
The product of its digits is 129600, while the sum is 36.
Adding to 53354344113 its reverse (31144345335), we get a palindrome (84498689448).
The spelling of 53354344113 in words is "fifty-three billion, three hundred fifty-four million, three hundred forty-four thousand, one hundred thirteen".
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