Search a number
-
+
53354391103 = 134104183931
BaseRepresentation
bin110001101100001010…
…110110011000111111
312002201100200220011101
4301230022312120333
51333232211003403
640302145433531
73566112561436
oct615412663077
9162640626141
1053354391103
112069a187802
12a41033b8a7
1350539b7030
14282202811d
1515c40dd71d
hexc6c2b663f

53354391103 has 4 divisors (see below), whose sum is σ = 57458575048. Its totient is φ = 49250207160.

The previous prime is 53354391029. The next prime is 53354391157. The reversal of 53354391103 is 30119345335.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 53354391103 - 29 = 53354390591 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53354391173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2052091953 + ... + 2052091978.

It is an arithmetic number, because the mean of its divisors is an integer number (14364643762).

Almost surely, 253354391103 is an apocalyptic number.

53354391103 is a deficient number, since it is larger than the sum of its proper divisors (4104183945).

53354391103 is a wasteful number, since it uses less digits than its factorization.

53354391103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4104183944.

The product of its (nonzero) digits is 72900, while the sum is 37.

The spelling of 53354391103 in words is "fifty-three billion, three hundred fifty-four million, three hundred ninety-one thousand, one hundred three".

Divisors: 1 13 4104183931 53354391103