Base | Representation |
---|---|
bin | 110001101100001011… |
… | …010011110001010011 |
3 | 12002201100221000020102 |
4 | 301230023103301103 |
5 | 1333232223331233 |
6 | 40302152203015 |
7 | 3566113602332 |
oct | 615413236123 |
9 | 162640830212 |
10 | 53354511443 |
11 | 2069a25a162 |
12 | a41039946b |
13 | 5053a29a3c |
14 | 2822059d19 |
15 | 15c41141e8 |
hex | c6c2d3c53 |
53354511443 has 4 divisors (see below), whose sum is σ = 53436976560. Its totient is φ = 53272046328.
The previous prime is 53354511421. The next prime is 53354511449. The reversal of 53354511443 is 34411545335.
53354511443 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 53354511443 - 214 = 53354495059 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 53354511397 and 53354511406.
It is not an unprimeable number, because it can be changed into a prime (53354511449) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41231588 + ... + 41232881.
It is an arithmetic number, because the mean of its divisors is an integer number (13359244140).
Almost surely, 253354511443 is an apocalyptic number.
53354511443 is a deficient number, since it is larger than the sum of its proper divisors (82465117).
53354511443 is an equidigital number, since it uses as much as digits as its factorization.
53354511443 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 82465116.
The product of its digits is 216000, while the sum is 38.
The spelling of 53354511443 in words is "fifty-three billion, three hundred fifty-four million, five hundred eleven thousand, four hundred forty-three".
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