Base | Representation |
---|---|
bin | 110001101100011110… |
… | …111101000000101001 |
3 | 12002201201121122020100 |
4 | 301230132331000221 |
5 | 1333240033123342 |
6 | 40302454420013 |
7 | 3566205431031 |
oct | 615436750051 |
9 | 162651548210 |
10 | 53359661097 |
11 | 206a2157176 |
12 | a412061609 |
13 | 5054b10982 |
14 | 28229da8c1 |
15 | 15c47cee4c |
hex | c6c7bd029 |
53359661097 has 24 divisors (see below), whose sum is σ = 77409652320. Its totient is φ = 35418936960.
The previous prime is 53359661083. The next prime is 53359661203. The reversal of 53359661097 is 79016695335.
53359661097 is a `hidden beast` number, since 5 + 33 + 596 + 6 + 10 + 9 + 7 = 666.
53359661097 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 53359661097 - 27 = 53359660969 is a prime.
It is not an unprimeable number, because it can be changed into a prime (53359661497) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2672929 + ... + 2692817.
It is an arithmetic number, because the mean of its divisors is an integer number (3225402180).
Almost surely, 253359661097 is an apocalyptic number.
It is an amenable number.
53359661097 is a deficient number, since it is larger than the sum of its proper divisors (24049991223).
53359661097 is a wasteful number, since it uses less digits than its factorization.
53359661097 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21173 (or 21170 counting only the distinct ones).
The product of its (nonzero) digits is 4592700, while the sum is 54.
The spelling of 53359661097 in words is "fifty-three billion, three hundred fifty-nine million, six hundred sixty-one thousand, ninety-seven".
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