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53361411 = 317787137
BaseRepresentation
bin1100101110001…
…1101100000011
310201102001002120
43023203230003
5102130031121
65143415323
71215364425
oct313435403
9121361076
1053361411
1128137244
1215a54543
13b0943cc
147130815
154a40bc6
hex32e3b03

53361411 has 4 divisors (see below), whose sum is σ = 71148552. Its totient is φ = 35574272.

The previous prime is 53361391. The next prime is 53361439. The reversal of 53361411 is 11416335.

53361411 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 53361411 - 25 = 53361379 is a prime.

It is not an unprimeable number, because it can be changed into a prime (53361461) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8893566 + ... + 8893571.

It is an arithmetic number, because the mean of its divisors is an integer number (17787138).

Almost surely, 253361411 is an apocalyptic number.

53361411 is a deficient number, since it is larger than the sum of its proper divisors (17787141).

53361411 is a wasteful number, since it uses less digits than its factorization.

53361411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17787140.

The product of its digits is 1080, while the sum is 24.

The square root of 53361411 is about 7304.8895268854. The cubic root of 53361411 is about 376.4804552039.

Adding to 53361411 its reverse (11416335), we get a palindrome (64777746).

The spelling of 53361411 in words is "fifty-three million, three hundred sixty-one thousand, four hundred eleven".

Divisors: 1 3 17787137 53361411