Base | Representation |
---|---|
bin | 111100101101011001000101… |
… | …0111101100001110010010101 |
3 | 2121000202022012012211222122110 |
4 | 1321122302022331201302111 |
5 | 1024443111103014400003 |
6 | 5131422051211421233 |
7 | 220323350005416531 |
oct | 17132621275416225 |
9 | 2530668165758573 |
10 | 534004205231253 |
11 | 145171a03434a19 |
12 | 4ba85713a54819 |
13 | 19bc74c3bb9483 |
14 | 95c1d27440bc1 |
15 | 41b0a1c946a03 |
hex | 1e5ac8af61c95 |
534004205231253 has 16 divisors (see below), whose sum is σ = 724503004522496. Its totient is φ = 349767413979840.
The previous prime is 534004205231243. The next prime is 534004205231323. The reversal of 534004205231253 is 352132502400435.
It is not a de Polignac number, because 534004205231253 - 28 = 534004205230997 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (534004205231243) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1663497301 + ... + 1663818282.
It is an arithmetic number, because the mean of its divisors is an integer number (45281437782656).
Almost surely, 2534004205231253 is an apocalyptic number.
It is an amenable number.
534004205231253 is a deficient number, since it is larger than the sum of its proper divisors (190498799291243).
534004205231253 is a wasteful number, since it uses less digits than its factorization.
534004205231253 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3327316524.
The product of its (nonzero) digits is 432000, while the sum is 39.
Adding to 534004205231253 its reverse (352132502400435), we get a palindrome (886136707631688).
The spelling of 534004205231253 in words is "five hundred thirty-four trillion, four billion, two hundred five million, two hundred thirty-one thousand, two hundred fifty-three".
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