Base | Representation |
---|---|
bin | 110001101110111010… |
… | …111100101010010101 |
3 | 12002211120120012221020 |
4 | 301232322330222111 |
5 | 1333331020213013 |
6 | 40310515111353 |
7 | 3600213135513 |
oct | 615672745225 |
9 | 162746505836 |
10 | 53400554133 |
11 | 20713247773 |
12 | a4238a2559 |
13 | 506042ab34 |
14 | 28282034b3 |
15 | 15c81ab623 |
hex | c6eebca95 |
53400554133 has 8 divisors (see below), whose sum is σ = 71202540000. Its totient is φ = 35599468848.
The previous prime is 53400554113. The next prime is 53400554147. The reversal of 53400554133 is 33145500435.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 53400554133 - 210 = 53400553109 is a prime.
It is a super-2 number, since 2×534005541332 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 53400554094 and 53400554103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53400554113) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 71883 + ... + 334616.
It is an arithmetic number, because the mean of its divisors is an integer number (8900317500).
Almost surely, 253400554133 is an apocalyptic number.
It is an amenable number.
53400554133 is a deficient number, since it is larger than the sum of its proper divisors (17801985867).
53400554133 is a wasteful number, since it uses less digits than its factorization.
53400554133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 450291.
The product of its (nonzero) digits is 54000, while the sum is 33.
The spelling of 53400554133 in words is "fifty-three billion, four hundred million, five hundred fifty-four thousand, one hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.064 sec. • engine limits •