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534043140131 = 777316870401
BaseRepresentation
bin1111100010101110111…
…00111010000000100011
31220001110101101102012102
413301113130322000203
532222210020441011
61045200325521015
753404041535634
oct7612734720043
91801411342172
10534043140131
11196539480556
1287601b7316b
133b48b05a487
141bbc261188b
15dd596a473b
hex7c5773a023

534043140131 has 4 divisors (see below), whose sum is σ = 534050088264. Its totient is φ = 534036192000.

The previous prime is 534043140073. The next prime is 534043140157. The reversal of 534043140131 is 131041340435.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 534043140131 - 234 = 516863270947 is a prime.

It is a super-2 number, since 2×5340431401312 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 534043140094 and 534043140103.

It is not an unprimeable number, because it can be changed into a prime (534043140731) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3357470 + ... + 3512931.

It is an arithmetic number, because the mean of its divisors is an integer number (133512522066).

Almost surely, 2534043140131 is an apocalyptic number.

534043140131 is a deficient number, since it is larger than the sum of its proper divisors (6948133).

534043140131 is an equidigital number, since it uses as much as digits as its factorization.

534043140131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6948132.

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 534043140131 its reverse (131041340435), we get a palindrome (665084480566).

The spelling of 534043140131 in words is "five hundred thirty-four billion, forty-three million, one hundred forty thousand, one hundred thirty-one".

Divisors: 1 77731 6870401 534043140131