5341135140401 has 4 divisors (see below), whose sum is σ = 5341141499904. Its totient is φ = 5341128780900.

The previous prime is 5341135140373. The next prime is 5341135140437. The reversal of 5341135140401 is 1040415311435.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5341135140401 - 2¹⁰ = 5341135139377 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5341135100401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1686065 + ... + 3677646.

It is an arithmetic number, because the mean of its divisors is an integer number (1335285374976).

Almost surely, 2^{5341135140401} is an apocalyptic number.

It is an amenable number.

5341135140401 is a deficient number, since it is larger than the sum of its proper divisors (6359503).

5341135140401 is an equidigital number, since it uses as much as digits as its factorization.

5341135140401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6359502.

The product of its (nonzero) digits is 14400, while the sum is 32.

The spelling of 5341135140401 in words is "five trillion, three hundred forty-one billion, one hundred thirty-five million, one hundred forty thousand, four hundred one".