Base | Representation |
---|---|
bin | 100110110111001010110… |
… | …0101110000100000011011 |
3 | 200220121110012122121120000 |
4 | 1031232111211300200123 |
5 | 1200002140414131443 |
6 | 15205405311504043 |
7 | 1060612530233661 |
oct | 115562545604033 |
9 | 20817405577500 |
10 | 5341154052123 |
11 | 177a19724528a |
12 | 723199828023 |
13 | 2c989009c9b6 |
14 | 146728464c31 |
15 | 93e07d788d3 |
hex | 4db9597081b |
5341154052123 has 10 divisors (see below), whose sum is σ = 7978760991564. Its totient is φ = 3560769368028.
The previous prime is 5341154052107. The next prime is 5341154052127. The reversal of 5341154052123 is 3212504511435.
5341154052123 is a `hidden beast` number, since 5 + 3 + 41 + 1 + 540 + 52 + 1 + 23 = 666.
5341154052123 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 5341154052123 - 24 = 5341154052107 is a prime.
It is not an unprimeable number, because it can be changed into a prime (5341154052127) by changing a digit.
It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 32970086661 + ... + 32970086822.
Almost surely, 25341154052123 is an apocalyptic number.
5341154052123 is a deficient number, since it is larger than the sum of its proper divisors (2637606939441).
5341154052123 is an equidigital number, since it uses as much as digits as its factorization.
5341154052123 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 65940173495 (or 65940173486 counting only the distinct ones).
The product of its (nonzero) digits is 72000, while the sum is 36.
Adding to 5341154052123 its reverse (3212504511435), we get a palindrome (8553658563558).
The spelling of 5341154052123 in words is "five trillion, three hundred forty-one billion, one hundred fifty-four million, fifty-two thousand, one hundred twenty-three".
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