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53413347949 = 134108719073
BaseRepresentation
bin110001101111101011…
…110000001001101101
312002212110122012202021
4301233223300021231
51333342304113244
640312053230141
73600426652333
oct615753601155
9162773565667
1053413347949
112071a495975
12a428032351
135062c8a240
142829bb3b53
1515c9387284
hexc6faf026d

53413347949 has 4 divisors (see below), whose sum is σ = 57522067036. Its totient is φ = 49304628864.

The previous prime is 53413347947. The next prime is 53413347973. The reversal of 53413347949 is 94974331435.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 94974331435 = 518994866287.

It can be written as a sum of positive squares in 2 ways, for example, as 32556789225 + 20856558724 = 180435^2 + 144418^2 .

It is a cyclic number.

It is not a de Polignac number, because 53413347949 - 21 = 53413347947 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 53413347896 and 53413347905.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53413347943) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2054359524 + ... + 2054359549.

It is an arithmetic number, because the mean of its divisors is an integer number (14380516759).

Almost surely, 253413347949 is an apocalyptic number.

It is an amenable number.

53413347949 is a deficient number, since it is larger than the sum of its proper divisors (4108719087).

53413347949 is a wasteful number, since it uses less digits than its factorization.

53413347949 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4108719086.

The product of its digits is 4898880, while the sum is 52.

The spelling of 53413347949 in words is "fifty-three billion, four hundred thirteen million, three hundred forty-seven thousand, nine hundred forty-nine".

Divisors: 1 13 4108719073 53413347949